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Voltman
06-26-2009, 10:50 PM
Calculate the molarity of the solution below.


2.1 g of NaHCO3 dissolved in 1.00 L of solution.



The answer 0.025 M but I got 0.058 M. Please show complete working out. Thank you!

Russ
06-27-2009, 02:20 AM
Molarity is number of moles (n) per litre (L) of solution.
Equation is M = n/L

n(NaHCO3) = 2.1/84

Since there is only 1L of solution, you need to divide by 1 to get the molarity (so the answer is .025)

84 is the formula mass of NaHCO3, derived from the formula;
n = m/M, m = mass and M = Formula Mass